Electronic Geometry of Lead(II) Chromate

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SUMMARY

The discussion centers on the electronic geometry of Lead(II) Chromate, specifically the valence electrons of chromium, lead, and oxygen in the compound. Chromium typically has 6 valence electrons, while lead has 4 and oxygen has 6. The participant raises a question regarding the Lewis dot structure, noting that lead appears to have only 2 electrons represented, which is inconsistent with its +2 charge. The ionic nature of Lead(II) Chromate suggests a transfer of 2 electrons from the chromate ion to the lead ion, confirming the ionic bond formation.

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The_ArtofScience
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I was wondering if anyone can solve this odd problem. Chromium is known to vary in the number of valence electrons and in this case, I would hope it has 6. Lead has 4 and oxygen 6. If you were to draw its Lewis dot structure with Chromium in the middle you would leave out Pb without any filled electrons which is to say, it's left with only a stick figure representing 2 electrons.


How does one go about in solving this problem?
 
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Shouldn't Lead(II) have 6 valence electrons since that is what gives it the +2 charge?
I'm not quite sure though, maybe someone who knows more can confirm that.
 
This compound is ionic in nature.
 
Then that would just mean a transfer of 2 electrons from the chromate ion to the lead ion.

Wow. My Chemistry is pretty rusty after a year of not doing it.
 

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