I was wondering if anyone can solve this odd problem. Chromium is known to vary in the number of valence electrons and in this case, I would hope it has 6. Lead has 4 and oxygen 6. If you were to draw its Lewis dot structure with Chromium in the middle you would leave out Pb without any filled electrons which is to say, it's left with only a stick figure representing 2 electrons. How does one go about in solving this problem?