Two equal charges of magnitude Q each are placed at a distance d apart .Their electrostatic energy is E. A third charge -Q/2 is brought midway between these two charges .The electrostatic energy of the system is now
EPE = kq1q2/r
The Attempt at a Solution
The question is quite simple and I have correctly found the answer which is -E i.e option B).
Now what is puzzling me is the signifance of negative electrostatic potential energy of this configuration . By definition of EPE , since energy of this configuration is negative then this means that when a unit test charge is brought from infinity towards the configuration, it experiences an attractive force .But from a far off point , the configuration should look like a net positive charge .Thus , configuration of these charges should repel test charge .
What is the significance of minus sign in the EPE of this configuration ?