Why Is Understanding Capacitor Equations Crucial?

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SUMMARY

Understanding capacitor equations is essential for calculating the voltage required to store a specific charge in a capacitor. In this discussion, a parallel plate capacitor with circular plates of diameter 0.3 meters and a separation of 0.00001 meters filled with water is analyzed. The relevant equation for capacitance is given as C = Q/U, where C is capacitance, Q is charge, and U is voltage. The dielectric constant of the material between the plates also plays a crucial role in these calculations.

PREREQUISITES
  • Knowledge of parallel plate capacitor equations
  • Understanding of dielectric constants
  • Familiarity with basic geometry (area of a circle)
  • Basic electrical concepts (charge, voltage, capacitance)
NEXT STEPS
  • Study the formula for capacitance of a parallel plate capacitor: C = ε(A/d)
  • Learn about dielectric materials and their impact on capacitance
  • Explore the relationship between charge, voltage, and capacitance in capacitors
  • Investigate practical applications of capacitors in electrical circuits
USEFUL FOR

Students studying electrical engineering, physics enthusiasts, and anyone looking to deepen their understanding of capacitor functionality and calculations.

Zeymare
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Homework Statement
There is a plate capacitor with round plates which have a diamter ov 0.3 meters and a plate distance of 0.00001 meters (or 0.01 mm). The Gap between both plates is filled with water. How high does the voltage on the capacitor have to be, to be able to save the charge of 0.001267 C (1.267 mC)? (one plate is positive, the other negative)
Relevant Equations
Capacity C = Charge Q/Voltage U
i didnt understand anything really, i read it a few times but i don't get it
 
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Its actually relly hard to put the question in english. But we need to use multiple things to be able to calculate that, for example the area of a Circle and the electric field constant. but i just don't know how everything ties together.
 
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Zeymare said:
Homework Statement:: There is a plate capacitor with round plates which have a diamter ov 0.3 meters and a plate distance of 0.00001 meters (or 0.01 mm). The Gap between both plates is filled with water. How high does the voltage on the capacitor have to be, to be able to save the charge of 0.001267 C (1.267 mC)? (one plate is positive, the other negative)
Relevant Equations:: Capacity C = Charge Q/Voltage U

i didnt understand anything really, i read it a few times but i don't get it
Welcome to the PF. :smile:

Can you show us the Relevant Equation for the Capacitance of a parallel plate capacitor in terms of the plate area and separation, and the value of the dielectric constant ##\epsilon## of the material filling the space between the plates?

And then what is the equation for the charge stored on a capacitor, in terms of the capacitance and the applied voltage? :smile:
 
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berkeman said:
Welcome to the PF. :smile:

Can you show us the Relevant Equation for the Capacitance of a parallel plate capacitor in terms of the plate area and separation, and the value of the dielectric constant ##\epsilon## of the material filling the space between the plates?

And then what is the equation for the charge stored on a capacitor, in terms of the capacitance and the applied voltage? :smile:
I am sorry for the late answer but i think i figured it out now. After you mentioned the equations, i researvhed a bit on google (because i didnt understand them in my book) and realized that i understood something completetly the wrong way and that's why i couldn't continue...so thank you
 
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