Electrostatics - Charged ball tied to a ceiling

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Homework Help Overview

The discussion revolves around a physics problem in electrostatics involving a charged ball suspended from a ceiling and influenced by an external electric field from a charged board. The problem requires determining the angle at which the cord holding the ball will lift due to the forces acting on it.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to analyze the forces acting on the ball by breaking them into components and applying trigonometric relationships. They express concern about discrepancies between their calculated angle and the textbook answer.

Discussion Status

Participants are engaged in reviewing the calculations and formulas used by the original poster. Some suggest that a simple arithmetic error may have occurred, while others point out potential confusion between trigonometric functions. There is no explicit consensus on the exact mistake, but guidance is being offered to recheck the calculations.

Contextual Notes

The problem involves specific values for mass, charge, and electric field density, which are critical for the calculations. The original poster's concern about the textbook answer indicates a need for careful verification of their approach and assumptions.

devanlevin
a ball with a mass of 100g is tied to a ceiling on a 1m cord and is charged with a positive charge of 3*10^16 c, what angle will the cord lift to if it is placed next to an infinite board charged with a density of 5*10-6 c/m^2 (positive), the board is placed at a constant angle of 45 degrees to the floor.

first i broke up the vectors of powers working on the ball,

Y+
Fcos45
Tcos(alpha)
--------
Y-
mg
-------
X+
Fsin45
-------
X-
Tsin(alpha)
--------
now i compare

Fsin45=Tsin(alpha)
T=Fsin45/sin(alpha)

mg=Fcos45+Tcos(alpha)
mg=Fcos45+(Fsin45/sin(alpha))*cos(alpha)
mg=Fcos45+Fsin45*cot(alpha)

cot(alpha)=(mg-Fcos45)/Fsin45

F=E*q
E=2(pi)(density)(k)
F=2(pi)(density)(k)(q)
F=0.27(pi)


once i put al the values in, i get that alpha=32.37 degrees but the answer in my textbook is not that, can you ssee where i have gone wrong
 
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devanlevin said:
once i put al the values in, i get that alpha=32.37 degrees but the answer in my textbook is not that, can you ssee where i have gone wrong
Your work looks OK to me, so recalculate that angle (just redo the arithmetic when you plug in your values). Looks like you've somehow found the complement of the angle, instead of the angle.
 


youre right, the answer in the book is 57 degrees, do you see where i have gone wrong
 


devanlevin said:
youre right, the answer in the book is 57 degrees, do you see where i have gone wrong
As I said, you must have made an arithmetic mistake. (I confirmed your formula and, using the same formula and values as you have, got the correct answer.) I suspect you mixed up cotangent with tangent.
 

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