- #1

rlc

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## Homework Statement

In the figure, two conducting balls of identical mass m = 20

*g*and identical charge q hang from nonconducting threads of length L = 100

*cm*. If x = 5.9

*cm*, what is q? Since x is much smaller than L approximate sin(θ) by θ.

## Homework Equations

Tcos theta = mg

Tsin theta = ((kq^2)/x^2)

(x/(2L) = (kq^2)/(mgx^2))

## The Attempt at a Solution

Tcos theta = mg

Tsin theta = ((kq^2)/x^2)

Tan theta = sin theta/cos theta

solve for tangent

(x/(2L) = (kq^2)/(mgx^2))

then solve for q

This is what a classmate of mine posted as a way to solve the problem, but it hasn't been working for me. Does this look like the right method? What does the T before cos and sin mean?

Is it necessary to calculate theta, by sin(theta)=(0.059m/2)/(1 m) ....theta=1.69 deg ?