Electrostatics -Electric Field and Potential

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SUMMARY

The discussion focuses on calculating the absolute potential at the center of a 30 cm diameter metal sphere, given an electric field strength of 3 MV/m at its surface. The correct approach involves using the formula for electric potential, V = kQ/r, where k is Coulomb's constant and r is the radius of the sphere. The error in the initial calculation stemmed from using the diameter instead of the radius, leading to the conclusion that the absolute potential at the center of the sphere is 450 kV, corresponding to option A.

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  • Understanding of electric fields and potentials
  • Familiarity with Coulomb's law and constants
  • Knowledge of basic geometry, specifically radius and diameter
  • Ability to manipulate algebraic equations
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This discussion is beneficial for physics students, electrical engineers, and anyone interested in understanding electrostatics and electric potential calculations.

abelthayil
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Homework Statement



A 30 cm diameter metal sphere hangs from a thread in the middle of a very large room. So its surroundings are essentially at infinity. If the electric field at tis surface is equal to the break down strength of air 3MV/m, what is the absolute potential at the center of the sphere?
A) 450 kV
B) 150 kV
C) 300 kV
D) 0

The answer is from what I've searched online is A


2. The attempt at a solution


The Electric FIeld at the surface is 3,000,000 V/m so kQ/r2=3,000,000
The only unknown is charge and solving we get Q=3*106*r2/k
where (k=1/4pi epsilon nought)

so potential at the centre =kQ/r=9* 105 V which is wrong so help please..
 
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Your method is correct, V=kQ/r, so E=kQ/r^2, V=Er...but you have to use r=0.15 m, instead of 0.3m. It is the radius.

ehild
 
Oh YES ! How silly of me Thanks !
 

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