1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Electrostatics problem (ruddy angles)

  1. Dec 4, 2006 #1
    1. The problem statement, all variables and given/known data
    Calculate the magnitude of the field strength at point P as shown. The distance between the centers of the 1.5E-6 C and the 9.2E-6 C charges is 5.6 cm..


    2. Relevant equations
    E = kq/r^2
    E = F/Q
    E = V/d


    3. The attempt at a solution
    Used tan and sin of 50 to find all distances

    E = kq/r^2
    E = (9E9)(1.5E-6C) / (7.31E-2 m)^2
    E = 2.526E6 N/C

    E = kq/r^2
    E = (9E9)(9.2E-6C) / (4.69E-2 m)^2
    E = 2.526E6 N/C

    then used those numbers to find c^2 using cosine law.

    I'm not getting a correct answer (obvoiusly).

    Thanks,
     

    Attached Files:

  2. jcsd
  3. Dec 4, 2006 #2
    picture is now working
     
  4. Dec 4, 2006 #3

    berkeman

    User Avatar

    Staff: Mentor

    What's a c^2 cosine law? You have the two vector components of the total E field. Do you know how to add the components? Is the answer expressed in polar or rectangular form?
     
  5. Dec 4, 2006 #4
    cosine law is:
    c^2 = a^2 + b^2 - 2ab cos c
    I dont know how to add the components or what polar/rectangular form is
     
  6. Dec 5, 2006 #5

    OlderDan

    User Avatar
    Science Advisor
    Homework Helper

    There is no way the fields from the two charges are the same. Your distances look OK.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Electrostatics problem (ruddy angles)
  1. Electrostatics problem (Replies: 2)

  2. Electrostatic problem (Replies: 4)

  3. Electrostatics problem (Replies: 2)

  4. Electrostatics Problem (Replies: 5)

Loading...