Electric field at a point problem

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SUMMARY

The discussion centers on calculating the electric field at a specific point due to three point charges: A (-5.00 nC), B (10.0 nC), and C (5.00 nC). The calculations involved using the formula E = kq/r^2 to determine the electric field contributions from each charge. The user initially arrived at a net electric field of 1.13x10^5 N/C at an angle of 32 degrees, which was incorrect due to improper vector addition of the components. The forum members emphasized the importance of maintaining symbolic calculations until the final step for clarity and accuracy.

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shadowdn
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Homework Statement


In the figure above, charge A is -5.00 nC, charge B is 10.0 nC, and charge C is 5.00 nC. If x = 2.10 cm and y = 4.20 cm, what is the electric field at the dot?
b6fef5347d1c4a67a10ca69b1fc87b17_A.jpg


Homework Equations


E = kq/r^2

The Attempt at a Solution


r = distance from A to point = sqrt(x^2+y^2)
Ea = kq/r^2 = -20'414.6 N/C
Ec = kq/x^2 = 102'040.8 N/C
Eb = kq/y^2 = 51'020.4 N/C
Eax = -20'414.6cos63.4 = -9'140.8 N/C
Eay = -20'414.6sin63.4 = -18'253.8 N/C
Enetx = Eax-Ec = -111'181.6 N/C
Enety = Eay-Eb = -69'274.2 N/C
Enet = sqrt[(-111'181.6)^2 + (-69'274.2)^2]
theta = tan^-1(Enety/Enetx) = 32 degrees

Final Answer (which was wrong): 1.13x10^5 @ 32 clockwise from horizontal

Can anyone tell me where I went wrong? Supposedly there is a special formula that I am supposed to use to find the components but I have never seen/used it before.
 

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shadowdn said:
Enetx = Eax-Ec
You calculated the individual contributions all on the basis of right and down are positive. So why are you performing a subtraction to find their sum?

Also, please get into the habit of working purely symbolically, not plugging in numbers until the end. It has many advantages, including making your work much easier to follow and verify.
 
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