How Does a Charged Particle Behave in a Non-Uniform Electric Field?

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A charged particle in a non-uniform electric field described by E = alpha – beta * x exhibits simple oscillatory motion. The amplitude of this motion is determined to be alpha/beta, with the mean position located at x = alpha/beta. Additionally, the maximum acceleration experienced by the particle is calculated as q*alpha/m. The discussion highlights the complexity of the problem, indicating that multiple solutions may exist. Understanding these dynamics is crucial for analyzing charged particle behavior in varying electric fields.
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A particle having mass m and charge q moves along a line under the action of an electric field E = alpha – beta *x where alpha and beta are positive constants and x is the distance from a point where the particle was initially at rest. Then, for an observer moving with acceleration q*alpha/m

1.) The motion of the particle is simple oscillatory
2.) The amplitude of the particle is alpha/beta
3.) The mean position of the particle is at x = alpha/beta
4.) The maximum acceleration of the particle is q*alpha/m

Please answer the question
 
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Please show your attempt at a solution.
 
well on working out the problem i got the answers 1) , but there is a multiple answer to the question
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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