Elliptically polarized light incident at Brewster's angle

[Alex Pedersen]

Elliptically polarized light strikes a glass surface (in air) with refraction index n at Brewster's angle.
What is the polarization of the reflected ray?
How does it change if now the glass surface is partially submerged in water?
And if the glass surface is fully submerged in water?
How would you proceed for the reflected ray to be linearly polarized?

The Attempt at a Solution

: [/B]If I understand correctly, when light strikes a glass surface at Brewster's angle, regardless of polarization, the reflected ray will be linearly polarized. And this doesn't change if the surface is fully submerged in whatever medium. But I'm not sure what happens when the surface is partially submerged.

 

[trurle]

Brewster angle is dependent on the ratio of the refraction indices of medium and glass.
tan(θp) = n2/n1
Therefore, submerging glass into water produce different (smaller) Brewster angle.