EM: Magnetic induction at a point due to a line of current, or square coil.

Click For Summary
SUMMARY

The discussion focuses on calculating the magnetic induction (B) at a field point due to a finite line of current using the Biot-Savart Law. The relevant equation derived is B = (μ₀I / 4πd)(cos θ₁ + cos θ₂), where μ₀ is the permeability of free space, I is the current, d is the perpendicular distance from the line of current to the field point, and θ₁ and θ₂ are angles related to the current line. The participant expresses confusion over the integration process and the variable changes in the example provided in their notes.

PREREQUISITES
  • Understanding of the Biot-Savart Law
  • Familiarity with vector calculus
  • Knowledge of magnetic fields and current-carrying conductors
  • Basic concepts of electromagnetism
NEXT STEPS
  • Study the derivation of the Biot-Savart Law in detail
  • Learn about the application of Ampere's Law in magnetic field calculations
  • Explore vector calculus techniques for solving integrals in electromagnetism
  • Investigate the differences between finite and infinite line currents in magnetic field generation
USEFUL FOR

Students of electromagnetism, physics educators, and anyone seeking to deepen their understanding of magnetic induction calculations in current-carrying conductors.

Seiun
Messages
1
Reaction score
0
Hi everyone,

(nb: I posted this in the introductory physics section, but maybe it should be here? I'm not exactly sure how to divide physics into introductory and advanced. I hope this isn't against the rules - it's only my second post!)

I am trying to understand my EM course again, and I have tried to solve this example for a couple of hours, but I cannot get the integration right. The example is in my notes, and is a worked problem... but the diagram is not very helpful, and I cannot see why particular changes of variable were made. Can anyone enlighten me on this problem?

I will try to explain the example, but a lot of my problem in understanding the example is the lack of a clear diagram and clear definition of the variables (in my opinion).

Let me know if I haven't said enough, keeping in mind that the example is not clear enough in my notes.

Homework Statement



The problem is to find the magnetic induction, B, at a point ("field point") due to a line of current. I guess you can assume the current continues to infinity, but the problem only considers from a point "a" to a point "b" on the line.

"dl" is a line element running from "b" to "a". The current "I" runs from "b" to "a". "r" is a vector running from the line element to the "field point". I assume this is the direction, an arrow has not been drawn but this is the standard definition, I believe. "d" is the shortest (perpendicular) distance form the line of current to the field point. \theta_{1} is the angle (smallest) between "r" at point "b" and the current line. Similarly, \theta_{2} is the angle (smallest) between "r" at point "a" and the current line.

I know this can easily be solved by Ampere's Law, however the example first uses the Biot-Savart law and produces a result that is used later on in a few occasions in the course.


Homework Equations



Biot-Savart Law:

<br /> B = \frac{\mu_0I}{4\pi}\int^{b}_{a} \frac{dl \times r}{r^{3}}<br />

3. Relevant Result

This is the relevant result from the above problem, and what's used later in the course.

<br /> B = \frac{\mu_0I}{4\pi d} ( \cos \theta_1 + \cos \theta_2 )<br />


Thanks!
 
Physics news on Phys.org
Well, it can't be an infinite line current because the magnetic field from an infinite line current is consant, right? If you are close enough to the wire it will look start to look like the infinite current line.

Maybe you can tell us where you start to get lost in the solution you have, or in your own work, and that will let us know where to start helping.
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
5
Views
2K
Replies
4
Views
4K
Replies
8
Views
1K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
10
Views
2K
  • · Replies 16 ·
Replies
16
Views
5K