Calculate Emf of Battery in Figure | Homework Problems and Solutions

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SUMMARY

The discussion focuses on calculating the electromotive force (emf) of a battery using Kirchhoff's laws. The user is provided with a current of 3.54 A and is advised to apply Kirchhoff's current law at junctions and Kirchhoff's voltage law for closed loops. The initial equation presented for emf calculation is incorrect, leading to confusion. The correct approach involves writing loop equations for both loops while considering the polarities of the voltage sources to accurately determine the emf.

PREREQUISITES
  • Understanding of Kirchhoff's Current Law (KCL)
  • Familiarity with Kirchhoff's Voltage Law (KVL)
  • Basic knowledge of circuit analysis
  • Ability to solve simultaneous equations
NEXT STEPS
  • Review Kirchhoff's Voltage Law applications in circuit analysis
  • Practice solving circuit problems involving multiple loops
  • Learn about the significance of voltage source polarities in circuit calculations
  • Explore techniques for solving simultaneous equations in electrical circuits
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Students studying electrical engineering, physics students tackling circuit analysis, and anyone seeking to understand battery emf calculations in practical applications.

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Homework Statement



What is the emf E of the battery at the lower left in the figure? Answer in units of V.


http://img508.imageshack.us/img508/6/82852928.png



Can someone guide me? I'm confused as to where to start. I think I am supposed go the route of the loop, but I am given the current as 3.54 A. How would I find the emf from there? TIA
 
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Label all currents. Then, write out Kirchoff's current law for each junction, and Kirchoff's voltage law for each closed loop. That should give you the right number of equations to solve for the emf.
 


So would it be:

\epsilon+(1.69x3.54)+(9.34x3.54)+(5.66x3.54)+(1.74x3.54)+11.88v=0
\epsilon=-77.44
 


Okay, that's wrong, I only have one more chance to put in the correct answer, so how would I do this?
 


Write the loop equations for both loops. Watch out for the polarities of the voltage sources. You're given one loop current, so there are still just two unknowns: the second loop's current and the voltage supply value.
 

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