Emf of a single loop wire around a solenoid

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SUMMARY

The discussion focuses on calculating the magnetic flux through a loop of wire surrounding a solenoid. The solenoid has a diameter of 4 cm, a length of 20 cm, 250 turns, and carries a current of 15 A. The magnetic field (B) is calculated using the formula B = μ₀ * (N * I) / L, resulting in a value of 0.0264 T. The magnetic flux (Φ) through the loop, which has a diameter of 10 cm, is determined to be 2.0735 x 10^-4 T*m² using the formula Φ = B * A * cos(θ).

PREREQUISITES
  • Understanding of magnetic flux and its calculation
  • Familiarity with solenoid properties and magnetic fields
  • Knowledge of the formula for magnetic field strength (B) in solenoids
  • Ability to calculate area (A) of a circle
NEXT STEPS
  • Study the derivation of the magnetic field inside a solenoid
  • Learn about the relationship between current, turns, and magnetic field strength
  • Explore applications of Faraday's Law of Electromagnetic Induction
  • Investigate the effects of varying current on magnetic flux
USEFUL FOR

Physics students, electrical engineers, and anyone studying electromagnetic theory will benefit from this discussion.

imatreyu
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Sorry, the title is wrong. Should be "magnetic flux" of a single loop wire around a solenoid.

Homework Statement



A solenoid 4 cm in diameter and 20 cm in length has 250 turns and carries a current of 15 A. It is surrounded by a loop of wire 10 cm in diameter. The loop is positioned perpendicular to and centered on the axis of the solenoid. Find the magnetic flux through the loop of wire. (The field outside of the solenoid is small enough to be negligible.)

Homework Equations



E= N*A*B*w*sinwt ?

The Attempt at a Solution



I don't know where to start...at all. How is there even an emf in the loop if the field around the solenoid is negligible?
 
Last edited:
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There's no EMF, but the question is asking for the flux. What's the definition of flux?
 
flux is BAcostheta.I'm confused on what to use for B. . .since there's no field created by the solenoid.
 
Are you sure the solenoid doesn't create a magnetic field?
 
Actually. . . if someone could check my work:

B= 4pi x 10^-7 * 1400 turns * 15 A
= .0264 T

flux = BA cos theta
=.0264 T * (.0025 pi m^2)
=2.0735 x 10^-4 T*m^2

Answer = 2.0735 x 10^-4 T*m^2
 
Last edited:

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