EMF, Power Output, and Terminal Voltage

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The discussion revolves around calculating the emf, total power output, and terminal voltage of a battery supplying a steady current of 5.6 A for 21 seconds, converting 1410 J of chemical energy into electric energy, with 560 J lost as heat. To find the emf, the user considers the total energy transformed into electric potential energy per coulomb of charge, debating whether to include the heat loss in the calculation. For total power output, the user suggests using the formula P=VI, where V represents the emf. The terminal voltage calculation remains unclear, but the user notes that power can also be expressed as a rate of energy over time. The discussion highlights the complexities of energy transformation in battery systems.
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Homework Statement


A battery supplies a steady current of 5.6 A for 21s. During this time 1410J of chemical energy is transformed into electric energy, but 560J of this electric energy is transformed into heat energy inside the battery.

a) What is the emf of the battery?

b) What is the total power output of the battery?

c) What is the terminal voltage fo the battery?


Homework Equations


emf= Ve + V
P= VI or P= V2/R
Ve= emf - V or Ve= emf- Ir

The Attempt at a Solution


My attempt to find the emf was (1410J)/(21s) and to multiply that by (1.6 X 10-19), since the emf is the "amount of chemical energy transformed to electric potential energy per coulomb of charge." However, I am not sure if I am to include or minus the 560J from the 1410J.
Then to find the power output, I am assuming that you would use P=VI, where the V is the emf.
After that, I don't know how to find the terminal voltage.
 
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Looks like you just stuck the charge of a single electron in there. You know P=VI, and you know power is just a rate of energy, P = E/t. That means you have everything you need.
 
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