Chemistry Homework - the empirical formula of crocetin

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Discussion Overview

The discussion revolves around determining the empirical formula of crocetin based on its combustion products, specifically carbon dioxide and water. Participants explore the methodology for calculating moles of elements involved in the reaction and how to derive the empirical formula from these values.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant expresses uncertainty about how to approach the problem after attempting it for 30 minutes.
  • Another participant suggests using the formulas of carbon dioxide and water to find the number of moles of each element produced, indicating that these will be equivalent to the moles before the reaction.
  • A clarification is made regarding the relationship between moles of water and moles of oxygen, with a participant questioning the wording used in the explanation.
  • Concerns are raised about the ambiguity in stating the number of moles of oxygen in carbon dioxide, highlighting the difference between moles of oxygen atoms and moles of oxygen molecules.
  • One participant suggests that while calculating the moles of oxygen from combustion products is valid, it is important to account for the oxygen that comes from the combustion process itself, proposing a different approach to find the mass of carbon and hydrogen first.
  • Another participant expresses frustration, stating they still do not understand the question and are under time pressure due to an upcoming test.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the best approach to solve the problem. There are competing views on how to account for the oxygen in the combustion reaction and how to derive the empirical formula from the data provided.

Contextual Notes

Some participants note limitations in the explanations provided, particularly regarding the assumptions made about the sources of oxygen in the combustion reaction and the clarity of the language used in describing the relationships between moles of different substances.

DavidQT
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Chemistry Homework -- the empirical formula of crocetin

Homework Statement



Crocetin consists of elements carbon, hydrogen and oxygen. Determine the empirical formula of crocetin, if 1.00g of crocetin forms 2.68g of carbon dioxide and 0.657g of water when it undergoes complete combustion.

Homework Equations



n=m/M,

The Attempt at a Solution


I have no idea how to do this question I tried for 30 min and I can't get anything.
 
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Use the formulas of carbon dioxide and water to find the number of moles of each element produced. This will be equivalent to the number of moles before the reaction. The ratio of these numbers to each other will tell you the empirical formula.

To explain it in more simple terms, water can be broken down into moles and so can carbon dioxide. Since there are two hydrogen atoms and one oxygen atom in a molecule of water, the number of moles in water will be equal to the number of moles of oxygen (because for 1 molecule of water there is 1 oxygen atom) and the number of moles of hydrogen will be twice the number of moles of water (because there are 2 hydrogen molecules in water).

The same goes for carbon dioxide. For 1 mole of carbon dioxide, there is one mole of carbon and two moles of oxygen. Take the number of moles of oxygen from each product and add them together to get the total number of moles of oxygen that you had before the reaction. The number of moles of each atom is conserved, so if you find how many moles of each are present after the reaction, you know how many moles there were before. Once you get how many moles of each element, you can find the ratio between them, which will give you the empirical formula.
 
DavidQT said:
I have no idea how to do this question I tried for 30 min and I can't get anything.

Google for empirical formula, plenty of tutorials on the web.
 
Lamebert said:
Use the formulas of carbon dioxide and water to find the number of moles of each element produced. This will be equivalent to the number of moles before the reaction. The ratio of these numbers to each other will tell you the empirical formula.

So far so good.

water can be broken down into moles

Huh?

number of moles in water will be equal to the number of moles of oxygen

I assume you mean "number of moles of water"?

The same goes for carbon dioxide. For 1 mole of carbon dioxide, there is one mole of carbon and two moles of oxygen.

Beware - two moles of oxygen can mean either two moles of oxygen atoms or two moles of oxygen molecules. These are two different things and you should be paying attention to you wording to avoid ambiguity.

Take the number of moles of oxygen from each product and add them together to get the total number of moles of oxygen that you had before the reaction.

Yes, but no. Yes, it will tell you how much oxygen was present before the reaction, but as it was a combustion reaction some of the oxygen came not from the molecule itself. Correct approach is to calculate mass of carbon and hydrogen in the original sample and to subtract these numbers from the original sample mass - whatever is left was most likely oxygen (unless the original compound contained also other, not mentioned elements).
 
Still Dont get iit

Ok I have a test tomorrow and I still don't get this question.
 
Blood hemoglobin contains 0.33% iron. Assuming that there are two atoms of iron per molecule of hemoglobin, calculate the approximate molecular weight of hemoglobin.

I don't get even how to start a question like this can someone tell me what their answer is and how they did it please.
 

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