Energy Calculations: P=VxIxt - Why Watts & not Joules?

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SUMMARY

The discussion clarifies the calculation of energy used by a lamp over a period of 6 hours using the formula P=V.I.t. The calculation provided, P=240V x 0.2A x 6hrs x 3600s, results in 1,036,800 Joules, confirming that energy is indeed measured in Joules, not Watts. Participants emphasize the importance of understanding that power (Watts) multiplied by time (seconds) yields energy (Joules). Dimensional analysis is recommended to verify unit conversions and ensure clarity in calculations.

PREREQUISITES
  • Understanding of electrical power formulas (P=V.I)
  • Knowledge of unit conversions between hours and seconds
  • Familiarity with the concept of energy in Joules
  • Basic skills in dimensional analysis
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  • Study the relationship between power, energy, and time in electrical systems
  • Learn about dimensional analysis techniques for unit conversions
  • Explore the SI unit definitions for Joules, Watts, and Amperes
  • Investigate practical applications of energy calculations in electrical engineering
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Students in physics or electrical engineering, educators teaching energy concepts, and anyone interested in understanding electrical energy calculations.

GSK
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The question:
Calculate the energy used by the lamp in 6 hours of use.

The answer:
P=V.I.t
P= 240v X 0.2A X 6hrs X 3600s

P= 1036800W!?

I thought energy was Joules? Why has the answer been given in watts? Please help!
 
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GSK said:
The question:
Calculate the energy used by the lamp in 6 hours of use.

The answer:
P=V.I.t
P= 240v X 0.2A X 6hrs X 3600s

P= 1036800W!?

I thought energy was Joules? Why has the answer been given in watts? Please help!
Welcome to the PF.

Please be sure to use the Homework Help Template that you are provided when starting schoolwork threads here at the PF. It makes it much easier for us to help you.

On your question, yes, energy should be in units of Joules. Can you post the full question?
 
The answer is indeed in joules
You have done a mistake
Power does not equal the energy applied okay??
It's power ×time which is equal to the energy used up
The expression which you gave gives the amount of energy used by the lamp in 6hours
If I were you I would convert 1 volt
As 1 joule/1 coulomb, 1 ampere as 1 coulomb/1 second
And then multiply these two with the total no.of seconds
As you can then clearly see
You are only left with the unit joules in your answer
You can perform dimensional analysis to further verify your answer!:)
UchihaClan13
 
GSK said:
P= 240v X 0.2A X 6hrs X 3600s
BTW, when doing unit conversions, it's best to just multiply by "1" and cancel units. So using 1 = 3600s/hr, you should have written:

E= 240V X 0.2A X 6hrs X 3600s/hr

And your answer is in units of V * A * s = Joules. :smile:
 
I'm really sorry, but I don't understand what you mean?

Why does 's/hr' then mean it converts to joules from watts?

Apologies, u have a challenge on ur hands with me.

My problem isn't physics, but maths. You're going to tell me they're the same huh?!
berkeman said:
BTW, when doing unit conversions, it's best to just multiply by "1" and cancel units. So using 1 = 3600s/hr, you should have written:

E= 240V X 0.2A X 6hrs X 3600s/hr

And your answer is in units of V * A * s = Joules. :smile:
m really
 
GSK said:
Why does 's/hr' then mean it converts to joules from watts?
s/hr means seconds/hour. You are just converting hr into s so that the unit of energy will be joule. In SI system, joule=V×A×s.
 
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