Energy conservation of a child on a swing

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SUMMARY

The maximum speed of a child on a swing is 4.9 m/s, with the child's height above the ground at the lowest point being 0.7 m. To determine the height at the highest point, energy conservation principles are applied. The discussion clarifies the cancellation of mass (m) in the equations, emphasizing that gravitational acceleration (g) only cancels in terms where it appears. The kinetic energy (KE) term remains unaffected by this cancellation.

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  • Understanding of basic physics concepts, particularly energy conservation
  • Familiarity with kinetic energy (KE) calculations
  • Knowledge of gravitational acceleration (g) and its role in motion
  • Ability to manipulate algebraic equations
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  • Study the principles of energy conservation in mechanical systems
  • Learn how to calculate potential energy (PE) and kinetic energy (KE) in various scenarios
  • Explore the concept of gravitational potential energy and its applications
  • Investigate the effects of mass and gravity on motion in physics
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mikefitz
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The maximum speed of a child on a swing is 4.9 m/s. The child’s height above the ground at the lowest point is 0.7 m. How high above the ground is he at his highest point?
http://img208.imageshack.us/img208/9949/untitledyx0.png

Above is the work done to solve the problem. I don't understand how they went from the blue to the red equation. Wouldn't the two g's cancel out since you would need to divide the left side by mg?
 
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mikefitz said:
Wouldn't the two g's cancel out since you would need to divide the left side by mg?
You divide all terms by mg. The m's all cancel, since an m appears in all three terms. But g's only cancel in the two terms that had g's--the KE term does not have a g to cancel.
 

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