Conservation of Mechanical energy

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SUMMARY

The discussion focuses on the conservation of mechanical energy in a system involving an 8.00 kg stone and a spring. The spring constant was calculated to be 784 N/m, and the elastic potential energy at the release point was determined to be 62.72 J. The main challenge presented was calculating the change in gravitational potential energy as the stone moves to its maximum height. The conservation of mechanical energy principle is emphasized, indicating that total mechanical energy remains constant throughout the stone's motion.

PREREQUISITES
  • Understanding of Hooke's Law (F = -kx)
  • Knowledge of gravitational potential energy (PE = mgh)
  • Familiarity with energy conservation principles
  • Basic algebra for solving equations
NEXT STEPS
  • Study the concept of mechanical energy conservation in physics
  • Learn how to derive the spring constant using Hooke's Law
  • Explore gravitational potential energy calculations in various contexts
  • Investigate the relationship between kinetic and potential energy in oscillatory systems
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators seeking to explain energy conservation concepts in practical scenarios.

mia_material_x1
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Homework Statement


Attached figrue shows an 8.00 kg stone at rest on a spring.The spring is compressed 10.0 cm by the stone.
(a) What is the spring constant?
(b) The stone is pushed down an additional 30.0 cm and released.What is the elastic potential energy of the compressed spring just before that release?
(c) What is the change in the gravitational potential energy of the stone–Earth system when the stone moves from the release point to its maximum height?
(d) What is that maximum height, measured from the release point?

Homework Equations


F = mg
F = -kx
W = 1/2 (kx²)

The Attempt at a Solution


m = 8kg
x1 = - 0.1m
x2= - 0.1m - 0.3m = -0.4m

Don't worry about a) and b), I've worked them out here just in case of reference
a) F=mg=-kx1 ⇒k=784 n/m
b) kΔx²/2= (784 n/m)(-0.1m-0.3m)²/2 = 62.72 J

What I have trouble with is c), can someone explain how I should deal with this question? (p.s, You are awesomeee if you can accompany your explanation with drawing) http://imgur.com/t4BkCe1

Much thanks!
 
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mia_material_x1 said:
What I have trouble with is c), can someone explain how I should deal with this question?
The title of your thread is a big hint! Mechanical energy is conserved. At the lowest point, what is the total mechanical energy? (Measure gravitational PE from that point.) At the highest point?
 

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