SUMMARY
The energy dissipated as heat by a 1.5 kΩ resistor with a constant 20 V potential difference over a 2-minute interval can be calculated using the formula for electrical power. The relevant equations include \( P = \frac{V^2}{R} \) for power and \( E = P \times t \) for energy, where \( P \) is power, \( V \) is voltage, \( R \) is resistance, and \( t \) is time. Substituting the values, the power is 0.267 W, leading to an energy dissipation of 32.04 J over the specified time period.
PREREQUISITES
- Understanding of Ohm's Law and electrical power calculations
- Familiarity with the formula \( P = \frac{V^2}{R} \)
- Knowledge of energy calculations using \( E = P \times t \)
- Basic concepts of resistors and voltage in electrical circuits
NEXT STEPS
- Study the derivation and application of Ohm's Law in circuit analysis
- Learn about the relationship between power, voltage, and resistance in electrical systems
- Explore energy dissipation in resistive components in detail
- Investigate the effects of varying voltage and resistance on energy dissipation
USEFUL FOR
Students studying electrical engineering, physics enthusiasts, and anyone involved in circuit design or analysis will benefit from this discussion.