The E in this formula is electric field, which you don't have in this problem.deltaV=-Ed
The energy dissipated as heat in a resistor is the energy that is lost as heat when an electric current passes through it. This is due to the resistance of the material in the resistor, which creates friction and causes the energy to be converted into heat instead of being used to power a device or circuit.
The energy dissipated as heat in a resistor can be calculated using the formula E = I^2 x R x t, where E is the energy dissipated (in Joules), I is the current (in Amperes), R is the resistance (in Ohms), and t is the time interval (in seconds). This formula is based on Ohm's law, which states that the current through a resistor is directly proportional to the voltage and inversely proportional to the resistance.
Energy dissipates as heat in a resistor due to the Joule heating effect. This is caused by the collisions of electrons with the atoms in the resistor's material, which results in the conversion of electrical energy into heat. The higher the resistance of the material, the more energy will be dissipated as heat.
The potential difference, or voltage, across a resistor determines the rate at which energy is dissipated as heat. The higher the potential difference, the more energy will be dissipated as heat in a given amount of time. This is because a higher potential difference results in a higher current flowing through the resistor, which leads to more collisions between electrons and atoms and thus more heat being generated.
No, energy dissipated as heat in a resistor cannot be recovered. This energy is lost and cannot be converted back into electrical energy. This is why resistors are often used in circuits to control the amount of energy that is dissipated as heat and prevent damage to other components that may be sensitive to high temperatures.