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## Homework Statement

Given a series circuit with a capacitor of capacitance C, a resistor of resistance R, a DC voltage source with a voltage V, and an open switch (by open I mean not connected so no current flows through). At t=0 the switch is closed. How much energy is dissapated by the resistor at t= infinity

## Homework Equations

C=Q/V

P

_{R}=iV

V=iR

i=dq/dt

## The Attempt at a Solution

First off my conceptual understanding of the problem is such: Initially, the voltage source provides a voltage that charges up the capacitor. Eventually, the capacitor charges all of the way up and the current goes to 0. So what I need to do is integrate the power that the resistor dissipated from t=0 to t=infinity

Using P

_{R}=iV and subbing in i=dq/dt.

The voltage can factor our of the integral since it is constant, and the dt's cancel

I end up with V times the integral of dq which equals VQ

Since Q=CV the answer I have is CV

^{2}

Now I have no idea if this is correct since it is a test review question so I was wondering if this looks correct to all of you. If not, as always, any input would be greatly appreciated.

Thanks!

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