Energy eigenvalues and ground-state energy

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Jenkz
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Homework Statement


The energy eigenvalues of a particles of mass, m, confined to a 3-d cube of side a are:

E[tex]_{nx,ny,nz}[/tex]=[tex]\frac{a(n^{2}_{x}+n^{2}_{y}+n^{2}_{z})}{b}[/tex]+ Vo

where:
a= planks constant^2(pi)^2
b=2m^2
nx,ny,nz = any positive integers.

What are the ground-state kinetic and potential energies of the particle.

The Attempt at a Solution


Really stumped. Any hints would be helpful thanks.
 
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Try starting with the kinetic and potential energy operators.
 
So
Ke = 3a(n[tex]^{2}_{x}[/tex]) /b ?

And Pe would be re-arranging to have Vo = E - 3a(n[tex]^{x}_{2}[/tex] )/b