Energy lost due to resistance?

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    Energy Lost Resistance
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SUMMARY

The discussion focuses on calculating energy loss due to resistance in an electrical system using the formula P = I²R. Given a voltage of 12 volts, a current of 0.42 Amps, and a resistance of 28.8 ohms, the energy loss can be determined by first calculating the power loss. The power loss in watts is calculated as P = (0.42)² * 28.8, which results in the energy lost per unit time. This formula is essential for understanding energy dissipation in electrical circuits.

PREREQUISITES
  • Understanding of Ohm's Law
  • Familiarity with electrical power calculations
  • Knowledge of units such as volts, amps, ohms, and joules
  • Basic grasp of electrical circuit components
NEXT STEPS
  • Research the implications of resistance on circuit efficiency
  • Learn about energy conservation in electrical systems
  • Explore advanced power loss calculations in AC circuits
  • Study the effects of temperature on resistance and energy loss
USEFUL FOR

Electrical engineers, physics students, and anyone involved in designing or analyzing electrical circuits will benefit from this discussion.

radaballer
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If electricity passes through a system at 12 volts, with 0.42 Amps of current, and 28.8 ohms of resistance, how do you calculate the energy lost in joules?
 
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radaballer said:
If electricity passes through a system at 12 volts, with 0.42 Amps of current, and 28.8 ohms of resistance, how do you calculate the energy lost in joules?

Power multiplied by time...
 
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[itex]P=I^2R[/itex] is energy loss per unit time.
 

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