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**'i' due to resistances in series**

We know If two or more resistances connected in series with an applied voltage 'V', then the equivalent resistance of the circuit is the sum of all the resistances. This is because all the resistors generates the same current.

==> V=IR1+IR2;

But why all the resistors in series are generating the same current, what is happening in the charge(Q) level. Why not one resistor takes more voltage and generate more current, and the another take low voltage and low current, such that they add upto voltage(V)

==>V=I1R1+I2R2;

Where I1>I and I2<I.

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