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'i' due to resistances in parallel

  1. Aug 21, 2010 #1
    'i' due to resistances in series

    We know If two or more resistances connected in series with an applied voltage 'V', then the equivalent resistance of the circuit is the sum of all the resistances. This is because all the resistors generates the same current.
    ==> V=IR1+IR2;

    But why all the resistors in series are generating the same current, what is happening in the charge(Q) level. Why not one resistor takes more voltage and generate more current, and the another take low voltage and low current, such that they add upto voltage(V)
    ==>V=I1R1+I2R2;

    Where I1>I and I2<I.
     
    Last edited: Aug 21, 2010
  2. jcsd
  3. Aug 21, 2010 #2
    First - resistors do not generate current. That is the wrong word.

    Resistors resist current flow - that's why we call them resistors.

    But the answer to your question is that the current that flows through the chain of resistors is the same for all of them. Current is the flow of charge - if (say) 100 electrons start at one end then 100 electrons will pass through each resistor in turn until they come out the end.
     
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