Energy (Potential, kinetic ) So stuck

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SUMMARY

The discussion centers on a physics problem involving two objects connected by a string over a frictionless pulley. The first object, m1 = 5.50 kg, is released from a height of 4.50 m, and the second object, m2 = 3.00 kg, is analyzed for its speed and maximum height after m1 hits the ground. The correct approach to solving part (b) involves recognizing that once m2 reaches the ground, the tension in the string disappears, allowing m1 to be treated as a projectile. The conservation of energy principle is essential for determining the maximum height reached by m1 after m2 hits the ground.

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Energy (Potential, kinetic...) So stuck :(

Homework Statement


Two objects, m1 = 5.50 kg and m2 = 3.00 kg, are connected by a light string passing over a light frictionless pulley as shown in the figure below. The object of mass 5.50 kg is released from rest, h = 4.50 m above the ground.

(a) Using the isolated system model, determine the speed of the 3.00 kg object just as the 5.50 kg object hits the ground. (I got 5.10 m/s)

(b) Find the maximum height to which the 3.00 kg object rises.

Homework Equations



K1+U1=K2+U2

The Attempt at a Solution



Part a was not a problem. It is part b that I'm stuck on. Common sense tells me that the maximum height that it will reach is equal to the height from which m2 is dropped. Apparently, my logic is faulty. So I tried the K1+U1=K2+U2 approach and am getting the wrong answer. I tried assuming that m2 had no potential energy when it reaches the bottom (and m1 would reach its maximum height), but wouldn't m2 also have no kinetic energy at the bottom, and m1 no kinetic energy at the top? And besides that, wouldn't their velocities be equal to zero, leaving me only with U1? I've literally been trying to figure this out for the last hour, what am I not seeing? Any help greatly appreciated!
 
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Hi zomething! Welcome to PF! :smile:
zomething said:
It is part b that I'm stuck on. Common sense tells me that the maximum height that it will reach is equal to the height from which m2 is dropped.

he he :biggrin:

when m2 hits the ground, the rope will go slack (ie no tension), so m1 will just be a projectile, launched upward …

find the speed of m1, and then use conservation of energy. :smile:

(alternatively, regard m2 as continuing to have the same KE as it had just before it hit the ground)
 

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