- #1

Fourier mn

## Homework Statement

Consider the 3-D infinite potential well (length=L). The energy levels for this system are given by E=(h bar)^2[tex]\pi^2[/tex]/(2ML^2)*(n(sub x)^2+(n(sub y)^2+(n(sub z)^2)

There are 10 particles in this potential well. What is the lowest energy of this ten-particle state when the particles are:

1. Identical, spinless bosons.

2. Identical, spin 1 bosons.

3. Identical fermions each with s=1/2

4. identical fermions each with spin s=1/2

## Homework Equations

None

## The Attempt at a Solution

I'm a little confused about bosons and fermions properties. If I remember correctly, bosons can be in the same state (all 10 of them) regardless of their spin or spinless. So for a. and b. the energy state would be 1 (the lowest) which all 10 particles are in the same state.

In the case of fermions, only two can be in the same state so the energy states go from 1 to five. I'm not sure how to proceed from here, and how to calculate the energy state. I'll really appreciate any suggestion.