Energy transfer by conduction through a window

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SUMMARY

The discussion focuses on calculating the rate of energy transfer through a glass windowpane using the equation P = kA(delta T/L). Given the thermal conductivity of glass as 0.84 W/(m·K), a window area of 2 m², and a temperature difference of 25˚C, the power calculated is 6774 J/s. For the total energy loss over one day, the calculation yields 5.85 x 108 Joules, confirming the accuracy of the method and equations used.

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Homework Statement


A glass windowpane in a home is 0.62 cm thick and has dimensions of 1.0 m x 2.0 m. On a certain day, the indoor temperature is 25˚C and the outdoor temperature is 0˚C.
a) What is the rate at which energy is transferred by heat through the glass?
b) How much energy is lost through the window in one day, assuming the temperatures inside and outside remain constant?

Homework Equations



For part a:
P = kA(delta T/L)

P = power (J/s)
k = thermal conductivity of glass, in my book it is 0.84
A = area of window = 2 m2
delta T = difference of temps from inside and outside window = 25oC
L = thickness of window = 0.0062 m

For part b:
q = P(delta T)

q = energy
P = power = 6774 J/S
delta T = 1 day = 86400 s

The Attempt at a Solution



When I solve this, I get 6774 J/s for part A, and 5.85 x 108 Joules for Part B.
Just wondering if I got the right answers/used the right equations. Thanks!
 
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That looks like the correct method to me.
 

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