Energy Uncertainty and expectation value of H

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SUMMARY

The discussion focuses on calculating the energy uncertainty and expectation value of the Hamiltonian operator for a quantum particle described by the wave function Psi(x,t=0) = A*[phi_1(x)-i*sin(x)]. The normalization constant A is determined to be 1/sqrt(2). The time-evolved wave function Psi(x,t) is derived using the time evolution equation, yielding Psi(x,t) = 1/sqrt(2)*[phi_1*e^(-i*E1*t/h-bar) - i*phi_2*e^(-i*E2*t/h-bar)]. The expectation value is calculated as (E1+E2)/2, while the energy uncertainty delta_E is approached using the formula Delta_E = Sqrt(-^2), with the challenge of correctly determining .

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Pikas
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Homework Statement


A particle at time zero has a wave function Psi(x,t=0) = A*[phi_1(x)-i*sin(x)], where phi_1 and phi_2 are orthonormal stationary states for a Schrödinger equation with some potential V(x) and energy eigenvalues E1, E2, respectively.
a) Compute the normalization constant A.
b) Work out Psi(x,t)
c) Compute <H> for Psi(x,t)
d) Compute delta_E, the energy uncertainty

Homework Equations



Delta_E = Sqrt(<E^2>-<E>^2)

The Attempt at a Solution


a) Set: 1 = <Psi(0)|Psi(0)> => A = 1/sqrt(2)
b) From previous: Psi(x,t=0) = 1/sqrt(2)*[phi_1 - i*phi_2]
Use the time evolution equation: Psi(x,t) = 1/sqrt(2)*[phi_1*e^(-i*E1*t/h-bar) - i*phi_2*e^(-i*E2*t/h-bar)]
c) Probability of measuring E1: P1 = |<phi_1|Psi(x,t)>|^2 = 1/2
Similarly, Probability of measuring E2: P2 = 1/2
Then <H> = P1*E1 + P2*E2 = (E1+E2)/2
d) For this one, I attempted to use the mentioned equation. However, I could not find <E^2>.
I thought it would be: (P1*E1)^2 + (P2*E2)^2, but this yields a negative values under the square root, which is not possible since the energy uncertainty is probability not imaginary.
Please help, thank you.
 
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Pikas said:
a) Set: 1 = <Psi(0)|Psi(0)> => A = 1/sqrt(2)
b) From previous: Psi(x,t=0) = 1/sqrt(2)*[phi_1 - i*phi_2]
Use the time evolution equation: Psi(x,t) = 1/sqrt(2)*[phi_1*e^(-i*E1*t/h-bar) - i*phi_2*e^(-i*E2*t/h-bar)]
c) Probability of measuring E1: P1 = |<phi_1|Psi(x,t)>|^2 = 1/2
Similarly, Probability of measuring E2: P2 = 1/2
Then <H> = P1*E1 + P2*E2 = (E1+E2)/2
That looks fine.

Pikas said:
d) For this one, I attempted to use the mentioned equation. However, I could not find <E^2>.
I thought it would be: (P1*E1)^2 + (P2*E2)^2, but this yields a negative values under the square root, which is not possible since the energy uncertainty is probability not imaginary.
Go back to the definition of ##\langle E^2 \rangle##, and see what you can get.
 
Thank you very much.
 

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