(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A small block is placed at height h on a frictionless ramp inclined at an angle theta. Upon being released, the block slides down the ramp and then falls to the floor (a distance y below the base of the ramp). A small hole is located a horizontal distance x from the end of the ramp.

From what height, h , should the block be released in order to land in the hole? Note: that the unknowns for this problem are x, y, and theta. Your answer should be an algebraic expression that starts with h=

2. Relevant equations

3. The attempt at a solution

I started out by using the fact that

mg(h+y)=(1/2)mv^2

working it out to

h= (v^2/2g)-Y

my issue is finding v^2, I know that (2gh)^1/2 is the final velocity for both mgh and mgy.. I need to eliminate the h somehow because it is on both sides, but I am unsure how to do so. I have used trig, but am having no luck. I already solved this problem once using kinematics, and found it to be much easier. Any help solving this with energy would be appreciated.

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# Homework Help: Energy Work Problem, all algebra

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