Enthalpy of Formation of Carbon Monoxide

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SUMMARY

The discussion centers on calculating the enthalpy of formation for carbon monoxide (CO) using Hess's Law. The provided reactions are C(gr) + O2(g) → CO2(g) with ΔH = -393.5 kJ mol-1 and CO(g) + ½ O2(g) → CO2(g) with ΔH = -283 kJ mol-1. By reversing the second equation to CO2(g) → CO(g) + ½ O2(g) (+283 kJ mol-1) and combining it with the first equation, the enthalpy of formation for CO can be determined. The final equation is C(gr) + ½ O2(g) → CO(g), with the resulting ΔH calculated as -110.5 kJ mol-1.

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  • Understanding of Hess's Law
  • Knowledge of thermodynamic equations
  • Familiarity with enthalpy changes
  • Basic chemistry concepts regarding combustion reactions
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  • Learn about enthalpy changes in chemical reactions
  • Explore the concept of standard enthalpy of formation
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Homework Statement


Using the information provided for energy changes associated with the formation
of carbon dioxide, calculate the enthalpy for the formation of carbon monoxide.

C(gr) + O2(g) → CO2(g) ΔH (-393.5 kJ mol-1)
CO(g) + ½ O2 (g) → CO2 (g) ΔH (-283 kJ mol -1)
C(gr) + ½ O2 (g) → CO(g) ΔH = ?


Homework Equations


None really.


The Attempt at a Solution


Reverse equation #2 to get CO2 (g) → CO(g) + ½ O2 (g) (+283 kJ mol -1). I think that's one of the steps anyway. Haven't done of these in ages. Do I sub in for CO2 in equation #1 and then add the enthalpy of formations? What's the next step?
 
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Combine first two equations in such a way they yield third.
 
Thanks for that.
 

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