Entropy and temperature of the system

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The discussion addresses a homework problem regarding the entropy of a system in the microcanonical ensemble, presenting a formula for entropy as W = (N!)/(n!(N-n)!)*3^n. Participants express confusion over the definition of entropy, noting that W appears to be a numerical value rather than a unit of entropy, which should be in Joules per Kelvin. It is clarified that entropy is defined as k_b*log(S), where S represents the number of states corresponding to a macroscopic state. The focus shifts to finding S as the key quantity of interest in the problem. The conversation emphasizes the need for clearer wording in the question to avoid misunderstandings.
PeterPoPS
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Homework Statement


... Show that the entropy of the system in the microcanonical ensemble is

W = \frac{N!}{n!(N-n)!}3^n

and obtain an expression for the temperature of the system. ...
N = number of molecules
n = number of molecules in orthostate

Homework Equations




The Attempt at a Solution


This question makes no sense, right? Because it says the entropy is W which is just a number, and entropy is in the units Joule/Kelvin
 
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It should probably be reworded. But entropy is defined as k_b*log(S) where S is the number of states corresponding to a given macroscopic state. The interesting quantity in the entropy is S and it looks like that's what they want you to find.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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