Entropy of a Fermi dirac ideal gas

Click For Summary
SUMMARY

The discussion focuses on deriving the entropy formula for a Fermi-Dirac ideal gas using the partition function. The key expression for the partition function is given as ln(Z) = αN + ∑ ln(1 + exp(-α - βEr)). The entropy S is defined as S = k(lnZ + β), where is defined as = -1/β ∂ln(Z)/∂Er. The participants explore the relationship between the partition function and entropy, ultimately leading to the expression S = k∑[ln() + (1 - )ln(1 - )] as the desired result.

PREREQUISITES
  • Understanding of statistical mechanics concepts, particularly Fermi-Dirac statistics.
  • Familiarity with partition functions and their role in thermodynamics.
  • Knowledge of entropy calculations in statistical physics.
  • Basic proficiency in calculus, particularly differentiation and summation techniques.
NEXT STEPS
  • Study the derivation of the partition function for Fermi-Dirac gases in detail.
  • Learn about the implications of the entropy formula in quantum statistical mechanics.
  • Explore the relationship between temperature, free energy, and entropy in thermodynamic systems.
  • Investigate advanced topics in statistical mechanics, such as Bose-Einstein statistics for comparison.
USEFUL FOR

Students and researchers in physics, particularly those specializing in statistical mechanics and thermodynamics, as well as anyone interested in the properties of Fermi-Dirac gases.

Dassinia
Messages
141
Reaction score
0
Hello

Homework Statement


From the expression of the partition function of a fermi dirac ideal gas
ln(Z)=αN + ∑ ln(1+exp(-α-βEr))
show that
S= k ∑ [ <nr>ln(<nr>)+(1-<nr>)ln(1-<nr>)


Homework Equations


S=k( lnZ+β<E>)
<nr>=-1/β ∂ln(Z)/∂Er
<E>=-∂ln(Z)/∂β

The Attempt at a Solution


I tried to start with
S=k( lnZ+β<E>)
But I don't know how we get to introduce the nr in that ?

Edit:
S=-dF/dT with F=-kTln(Z)
I wrote ln(Z) in terms of nr
ln(Z)=α ∑<nr>-∑ln(<nr>)
But I don't get to the result
I get at the end
S= kα∑<nr>-k∑ln(<nr>)+kα∑(1-<nr>)

Thanks
 
Last edited:
Physics news on Phys.org
I suggest moving this to the advanced physics forum.
 

Similar threads

Replies
1
Views
1K
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
14
Views
2K
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K