Entropy of system with ice cube in lake

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Homework Help Overview

The discussion revolves around calculating the variation of entropy in a system involving a 10g ice cube at -10°C placed in a lake at 15°C. The specific heat of the lake is provided, and participants are exploring the thermodynamic principles involved in reaching thermal equilibrium.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply an integral involving temperature to calculate entropy change but expresses confusion about the equation and its implications. Other participants question the mathematical steps involved, particularly regarding the relationship between derivatives and integrals.

Discussion Status

Participants are actively engaging with the mathematical concepts related to entropy and calculus. Some guidance has been offered regarding the integral and its connection to logarithmic functions, though there is no clear consensus on the best approach to the problem.

Contextual Notes

There is an emphasis on showing work for homework-type problems, and one participant notes a language barrier that may affect communication. The original poster clarifies that their inquiry is more of a doubt rather than a formal homework question.

Brunno
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An ice cube of 10g -10°C is placed in a lake that is 15°C.Calcule the variation of entropy of the system when the ice cube to reach the thermal balance with the lake.
The specific heat of the lake is 0,50cal/g°C.:biggrin:
 
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You have to show your work in order to get help on homework type problems here.

What have you tried so far?

Also, next time, please post homework type problems in the appropriate homework help forum.
 


Ok,GO1,
I'll tell you,You might have thought about my bad English( I'm far way from you).For that,I'm sorry I really don´t write it well.:shy:.But it´s understood what you said!
Well,what have I tried so far?
This:
m*c\int_{Ti}^{T_f}\frac{dT}{T}
But I really don't understand nothing after it.I do know some concepts about derivative,but can you explain the equation above?And it's not a homework,it's just a doubt.
Thank you!
 


Anyone?
 


Ok,
Could somebody show me the why the darivative of \frac{dT}{T} is equal to ln\frac{T_f}{T_i}??
 


Brunno said:
Ok,
Could somebody show me the why the darivative of \frac{dT}{T} is equal to ln\frac{T_f}{T_i}??

It is the integral, not the derivative that you are finding.

HINT:
Start by letting y=ln(x)

Therefore, x=e^y

Take the derivative of both sides and you should be able to solve for dy/dx and derive the result your questioning. Specifically,

\frac{d \ln(x)}{dx}=\frac{1}{x}

So, when finding the this anti-derivative, we have:

\int\frac{dx}{x}=\ln{x} + C

This is a good formula to remember. If you don't remember, or have never learned this, you should probably review your calculus. Not knowing calculus like this will really hinder you as you try to learn more physics.
 
Last edited:

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