- #1
jaumzaum
- 434
- 33
I learned ΔSuniv = ΔSsys + ΔSneib
If ΔSuniv > 0 the process is spontaneous.
But ΔS = Q/T right? Shouldn't Qsys = -Qneib? (The heat released by the system = - heat released by the neighborhood)
I cannot understand why this is wrong!
If it were the case, ΔSuniv would be always zero
Can anyone help me?
[]`s
John
If ΔSuniv > 0 the process is spontaneous.
But ΔS = Q/T right? Shouldn't Qsys = -Qneib? (The heat released by the system = - heat released by the neighborhood)
I cannot understand why this is wrong!
If it were the case, ΔSuniv would be always zero
Can anyone help me?
[]`s
John