Epicyclic gear train- finding teeth

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SUMMARY

The discussion focuses on calculating the number of teeth in an epicyclic gear train, specifically for a design requiring a gear ratio of 1:100 with gear D having 100 teeth. The fixed annulus gear (c) and the input gear (A) rotating at 60 RPM with a torque of 10 Nm and 80% efficiency are key parameters. The relationship between the teeth on the gears is defined by the equation tc = td + 2tb, where td is 60 and tb is 130. The challenge lies in determining the unknowns for the number of teeth on gear c and the planet gears.

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Homework Statement


A gear ratio is req from A/D of 1:100 and that it will be necessary to redesign D so that it has 100 teeth. Determine:
a)number of teeth on c
b)number of teeth on planet gears.

This followed on from another question.
An epicyclic gear c is the annulus and is fixed. The input A rotates at 60rpm, torque of 10Nm. Efficiency 80%.
Teeth on td=60
Teeth on tb=130

Homework Equations


I can't see how to work out teeth using tc=td+2tb when there are two unknowns.
Any help will be gratefully recieved.
Thanks

The Attempt at a Solution

 
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Can anyone help with my question please? I am totally stuck!
 
can anyone help me please!
 

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