- #1
Marin
- 193
- 0
Hi all!
I´m having some trouble finding a delta for f(x)=(x-2)² using the epsilon-delta definition for fixed epsilon and x_0. Here´s what I come up with:
[tex]|f(x)-f(x_0)|<\epsilon[/tex]
[tex]|(x-2)^2-(x_0-2)^2|=|x^2-4x+4-x_0+4x_0-4|=|x^2-x_0^2-4(x-x_0)|=|(x-x_0)(x+x_0)-4(x-x_0)|=|x-x_0||x+x_0-4|<\epsilon[/tex]
now I divide by the second term and define my delta with the fixed epsilon and x_0, but there also appears this x which by definition should not be there, should it?
[tex]|x-x_0|<\frac{\epsilon}{|x+x_0-4|}:=\delta[/tex]
so, how can I make x disappear and thereby get some delta for my epsilon?
thanks a lot in advance!
I´m having some trouble finding a delta for f(x)=(x-2)² using the epsilon-delta definition for fixed epsilon and x_0. Here´s what I come up with:
[tex]|f(x)-f(x_0)|<\epsilon[/tex]
[tex]|(x-2)^2-(x_0-2)^2|=|x^2-4x+4-x_0+4x_0-4|=|x^2-x_0^2-4(x-x_0)|=|(x-x_0)(x+x_0)-4(x-x_0)|=|x-x_0||x+x_0-4|<\epsilon[/tex]
now I divide by the second term and define my delta with the fixed epsilon and x_0, but there also appears this x which by definition should not be there, should it?
[tex]|x-x_0|<\frac{\epsilon}{|x+x_0-4|}:=\delta[/tex]
so, how can I make x disappear and thereby get some delta for my epsilon?
thanks a lot in advance!