- #1

Arnoldjavs3

- 191

- 3

## Homework Statement

##\int_{-1}^{3} f(x) dx = -4 = \int_{-1}^{3} 2g(x)dx##

Now find a value(constant a) that makes the following true:

##\int_{-1}^{3} [3f(x) - ag(x) +a] dx = \int_{-1}^{3}(1-ax)dx##

## Homework Equations

## The Attempt at a Solution

I'm unsure if my approach here is correct but I think that I need to utilize the fact that ##\int_{-1}^{3} f(x) dx## = -4 and substitute this into the left side of equation? So I would get something like this after evaluating:

##\int_{-1}^{3} [-12+2a+a] dx## and then once I've done this, i can solve the integral. I'll have to solve the integral on the right side as well and once I've finished that, I find a value for a? I got 52/16 but I don't have an answer to check to.