MHB Equation and Point Check for Circle of Radius 1

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The equation of a circle with a radius of 1 centered at (0,0) is x^2 + y^2 = 1. The point (3/5, 4/5) is checked by substituting its coordinates into the equation. The calculation shows that (3/5)^2 + (4/5)^2 equals 1, confirming the point lies on the circle. The discussion concludes affirmatively that the point is indeed on the circle. The verification process is accurate and straightforward.
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A. Write the equation of radius 1 centered at (0,0).

x^2 + y^2 = 1

B. Does the point (3/5, 4/5) lie on the circle?

(3/5)^2 + (4/5)^2 = 1

(9/25) + (16/25) = 1

25/25 = 1

1 = 1

Yes, the point (3/5, 4/5) lies on the circle.

Correct?
 
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RTCNTC said:
Correct?

Yep. :)
 

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