Equation For Charging Current In Accumulator

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Homework Help Overview

The discussion revolves around deriving the equation for the charging current in an accumulator within a circuit that includes an external direct current (d.c.) supply and the internal resistances of both the supply and the accumulator. Participants explore the relationships between the electromotive forces (e.m.f) and resistances involved in the charging process.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the overall e.m.f in the circuit as the difference between E1 and E2, and the total resistance as the sum of r1 and r2. There are attempts to express the charging current in terms of these variables. Questions arise regarding the correctness of the initial equations presented and the principles behind the relationships between the voltages.

Discussion Status

There is an ongoing exploration of the relationships between the e.m.f and resistances, with some participants providing equations for the charging current. However, there is no explicit consensus on the derivation or the principles supporting the equations discussed. Clarifications and further inquiries are being made regarding the underlying concepts.

Contextual Notes

Participants are working within the constraints of homework guidelines, which may limit the depth of solutions provided. There is a focus on understanding the principles of voltage in series and how they apply to the charging of the accumulator.

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Homework Statement



Suppose we have a circuit represented, which is used for charging an accumulator from a.d.c supply of e.m.f, E1 and internal resistance, r1. If the e.m.f of the accumulator is E2 with an internal resistance of r2, then the equation for the charging current is what?
In this question, I want to know how to derive the equation for charging current in an accumulator.


Homework Equations



I know that there is equation that goes like this:
E = V + v
E = IR + ir
E = I(R + r)
I = E/(R + r)
But am not sure the above equation relates to my question in any way. Am optimistic that there are other equation that will be fit enough for this my questions.

The Attempt at a Solution



E = V + v
E = IR + ir
E = I(R + r)
I = E/(R + r)
but I don't think that this my working is correct or is fit for the question. Any help?
 
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I would say that the overall emf = E1-E2 and the total resistance - r1+r2.
So the current will be (E1-E2)/(r1+r2)
This checks out because when the battery is charged E2 = E1 and the current will then be zero
 
Emilyjoint said:
I would say that the overall emf = E1-E2 and the total resistance - r1+r2.
So the current will be (E1-E2)/(r1+r2)
This checks out because when the battery is charged E2 = E1 and the current will then be zero

Can you make the current, I the subject of the formula in any of the equation?
 
Emilyjoint said:
I would say that the overall emf = E1-E2 and the total resistance - r1+r2.
So the current will be (E1-E2)/(r1+r2)
This checks out because when the battery is charged E2 = E1 and the current will then be zero

Thank you so much. I understand from your reply that the current, I = (E1-E2)/(r1+r2)
I would say that the overall emf = E1-E2
But why is the overall emf = E1-E2? Can you give a principle that supports that?
 
Basically, voltages in series ADD. Here, you have one of opposite polarity to the other, in order to charge the accumulator correctly.

So, for a loop, the loop source voltage = the sum of the individual voltage sources
 

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