Equation for Final Position and Distance on a Velocity vs Time Graph

  • Thread starter Thread starter Drewser
  • Start date Start date
  • Tags Tags
    Final Position
Click For Summary
SUMMARY

The discussion centers on determining the final position and distance traveled using a velocity vs time graph. The key equation for finding the distance traveled over a time interval from ti to tf is given by the integral titf v(t) dt, where v(t) represents the velocity function. For a linear velocity graph, the equation can be derived from the slope-intercept form y = mx + b. The user also mentions a specific case where the distance calculated is 22 meters.

PREREQUISITES
  • Understanding of calculus, specifically integration
  • Familiarity with velocity vs time graphs
  • Knowledge of linear equations and their graphical representation
  • Basic physics concepts related to motion in one dimension
NEXT STEPS
  • Study the principles of calculus, focusing on definite integrals
  • Learn how to derive equations from velocity vs time graphs
  • Explore the relationship between acceleration and velocity
  • Investigate real-world applications of motion equations in physics
USEFUL FOR

Students studying physics, particularly those focusing on kinematics, as well as educators and tutors looking for effective methods to teach motion concepts using graphs.

Drewser
Messages
2
Reaction score
0

Homework Statement


Do you know the equation to find final position on a velocity vs time graph

Plus on the same graph how do you find the distance traveled, equation wise too from 4 seconds to 15 seconds?


Homework Equations



No idea

The Attempt at a Solution



22 meters but all I need are the equations
 
Physics news on Phys.org
No, you don't need any magic equations. Is your graph of velocity a straight slope? Would you know how to find an equation from a graph with y = mx + b?

Don't just ask for equations without any work or thoughts about anything because I might as well assume you could solve this
\dot{y} = \dot{y}(0) + at
 
Is this in one dimension?

if velocity is given by v(t) = dx(t)/dt, then distance traveled in time interval between ti and tf is given by

\int_{t_i}^{t_f}\,v(t)\,dt

where ti is the initial time and tf is the final time.

This assumes no acceleration.
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
600
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
3
Views
974
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 2 ·
Replies
2
Views
13K
  • · Replies 8 ·
Replies
8
Views
4K