A thin rod (uniform density and thickness)
with mass M and length L attached to floor at a fixed location by a frictionless hinge.
while balanced vertically the gravitational torque acting on the rod is
b.) 1/2 MgL
I know that torque is F x D(or L)
and a is g in this case,
so T= MgL
The Attempt at a Solution
as stated above I got to T=MgL
but I don't understand where the fractions are coming from? can someone please explain this?