- #1

- 3

- 0

## Homework Statement

A thin rod (uniform density and thickness)

with mass M and length L attached to floor at a fixed location by a frictionless hinge.

while balanced vertically the gravitational torque acting on the rod is

a.) zero

b.) 1/2 MgL

c.)1/3 MgL

d.)1/4 MgL

e.)1/6 MgL

## Homework Equations

I know that torque is F x D(or L)

F=Ma

and a is g in this case,

so T= MgL

## The Attempt at a Solution

as stated above I got to T=MgL

but I don't understand where the fractions are coming from? can someone please explain this?