Equation of a curve in 3 dimensions

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SUMMARY

The discussion focuses on determining the equation of a curve in three dimensions for a heat-seeking missile located at (2, -3) on a plane, guided by the temperature function T(x, y) = 20 - 4x² - y². The missile's trajectory follows the direction of the temperature gradient, which is calculated as the vector (-8x, -2y). The challenge lies in expressing the equation in the form x = f(y) while utilizing the gradients to derive the path equation.

PREREQUISITES
  • Understanding of gradient vectors in multivariable calculus
  • Familiarity with temperature functions and their implications in physics
  • Knowledge of implicit differentiation techniques
  • Ability to manipulate equations to express variables in terms of others
NEXT STEPS
  • Study the concept of gradient vectors and their applications in optimization problems
  • Learn about implicit differentiation and how to apply it to find curves
  • Explore the relationship between temperature gradients and motion in physics
  • Investigate the use of parametric equations to describe curves in three dimensions
USEFUL FOR

This discussion is beneficial for students in calculus or physics, particularly those studying optimization and motion along curves, as well as educators seeking to clarify the application of gradients in real-world scenarios.

sdevoe
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Homework Statement


A heat-seeking missile is located at (2,-3) on a plane. The temperature function is
given by T(x; y) = 20-4x^2-y^2. Find the equation of the curve along which the
missile travels, if it continuously moves in the direction of maximum temperature
increase. Express your answer in the form x = f(y). Show the calculations.


Homework Equations



T(x; y) = 20-4x^2-y^2

The Attempt at a Solution


I know the missile will travel along the direction of the gradient. The gradient with respect to x is -8x and the gradient with respect to y is -2y. The problem I'm having is getting the equation in terms of x. My only idea is to take δx(2,-3)(x-2)+δy(2,-3)(y+3)=0 and solve for x where x and δy are the gradients with respect to x and y. Is that correct?
 
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sdevoe said:
I know the missile will travel along the direction of the gradient. The gradient with respect to x is -8x and the gradient with respect to y is -2y.

The missile moves in the direction of the temperature gradient at any point of its path. That means that its velocity points in the direction of the gradient vector. But the velocity is tangent to the path. How do you get the tangent of a curve y=f(x)?


ehild
 

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