- #1

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(you are given the equation of the line and the curve)

x^3

3x-y-6

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- Thread starter QUITE RIGHT
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- #1

- 8

- 0

(you are given the equation of the line and the curve)

x^3

3x-y-6

- #2

Mentallic

Homework Helper

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Ok so you know the gradients have to be the same, so wherever the gradient is 3 on the curve (finding where this happens will be done by using the derivative) will be used to find the equation of the new line.

Taking the derivative of the curve will give you [tex]y'=3x^2[/tex]

and since this has to be equal to the gradient of the line which is 3, just solve [tex]3x^2=3[/tex].

Notice you'll have 2 answers, and that is how it should be!

And use the point-gradient form for the equation of a line:

[tex]y-y_1=m(x-x_1)[/tex]

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