Equation of Circle Through Origin

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SUMMARY

The equation of a circle passing through the origin with center at (3, 5) is derived using the distance formula to find the radius. The radius, denoted as r, is calculated as r = sqrt{(3 - 0)^2 + (5 - 0)^2}, resulting in r = sqrt{34}. The standard form of the circle's equation is then expressed as (x - 3)^2 + (y - 5)^2 = 34. This formulation is essential for understanding the geometric properties of circles in a Cartesian plane.

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  • Understanding of the distance formula in coordinate geometry
  • Familiarity with the standard equation of a circle
  • Basic knowledge of Cartesian coordinates
  • Concept of radius in circle geometry
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  • Learn about the properties of circles in analytic geometry
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mathdad
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Find the equation of the circle passing through the origin with center (3, 5).

Can someone get me started? Must I use the point (0, 0) here?
 
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RTCNTC said:
Find the equation of the circle passing through the origin with center (3, 5).

Can someone get me started? Must I use the point (0, 0) here?

If the center of the circle is at (3, 5) and one of the points on the circle is (0, 0), then how can we find the radius of the circle? In a circle, just what is the radius? How it is defined?
 
MarkFL said:
If the center of the circle is at (3, 5) and one of the points on the circle is (0, 0), then how can we find the radius of the circle? In a circle, just what is the radius? How it is defined?

The radius is the distance between the origin and given point.
 
RTCNTC said:
The radius is the distance between the origin and given point.

The radius is the distance between the center of the circle and any point on the circle. Since we are given the center and a point on the circle, we can determine the radius. :D
 
MarkFL said:
The radius is the distance between the center of the circle and any point on the circle. Since we are given the center and a point on the circle, we can determine the radius. :D

Let r = radius

r = sqrt{(3 - 0)^2 + (5 - 0)^2}

r = sqrt{3^2 + 5^2}

r = sqrt{9 + 25}

r = sqrt{34}

- - - Updated - - -

(x - h)^2 + (y - k)^2 = r^2

(x - 3)^2 + (y - 5)^3 = (sqrt{34})^2

(x - 3)^2 + (y - 5)^2 = 34

Correct?
 
Looks good to me. (Yes)
 
Instead of posting every question in the David Cohen precalculus textbook, I will post essential questions, questions that every student should know how to solve before going to calculus 1. There is no time to waste.
 

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