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- Thread starter snellslaw
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- #2

tiny-tim

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instead of the easy case of the force on an oscillator being proportional to its displacement,

it's a function of the displacements of itself

- #3

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Thanks TinyTim! So is "a" the spring constant?

- #4

tiny-tim

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there are n^{2} a's

- #5

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So are the "a"s just constants?

x is the displacement from equilibrium right?

Thanks! :)

x is the displacement from equilibrium right?

Thanks! :)

- #6

tiny-tim

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- #7

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[itex]\ddot{x_{1}}=a_{11}x_{1}+a_{12}x_{2}+a_{13}x_{3}[/itex]

[itex]\ddot{x_{2}}=a_{21}x_{1}+a_{22}x_{2}+a_{23}x_{3}[/itex]

[itex]\ddot{x_{3}}=a_{31}x_{1}+a_{32}x_{2}+a_{33}x_{3}[/itex]

Where i = 1 to 3 and j = 1 to 3. You have 3 equations with 3 unknown, and can solve this using the matrix determinant method.

Regards.

- #8

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@mps: hey are you preparing for the same thing? :P

Thanks everyone!

Thanks everyone!

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