Equation of velocity on transverse wave

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SUMMARY

The discussion focuses on deriving the equation for transverse wave velocity, specifically the relationship v = (F/μ)^(1/2), where F represents the tension in the string and μ denotes the linear mass density. Participants clarify that the equation pertains to transverse velocity, not phase velocity, and emphasize the importance of understanding the second derivative of displacement (d²y/dx²) in the context of wave motion. The derivation involves analyzing the net forces acting on adjacent segments of the string, leading to the wave equation.

PREREQUISITES
  • Understanding of wave mechanics and wave equations
  • Familiarity with calculus, specifically partial derivatives
  • Knowledge of tension and linear mass density in strings
  • Basic principles of forces acting on a string in motion
NEXT STEPS
  • Study the derivation of the wave equation in detail
  • Learn about the relationship between tension and wave speed in strings
  • Explore the concept of phase velocity versus transverse velocity
  • Investigate the implications of the second derivative in wave motion
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Physics students, educators, and anyone interested in understanding the dynamics of transverse waves and their mathematical representations.

Joza
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I am deriving the equation for a transverse wave velocity from the difference in the transverse forces acting on a string. ie. v=(F/Greek letter mu)^(1/2) :redface:

First of all, can I clear up that this refers to transverse velocity yes, and not phase velocity? (My book isn't clear).These are all partial derivatives by the way, so i presume it's all to do with transverse velocity and not phase since we keep x constant?


I can't really right the entire equation out, so I'll do my best.

So, I end up with an equation with (d^2y/dx^2) = (F/(mu)) (d^2y/dt^2)
and then you compare this to the wave equation.

I don't understand where the left side comes from. The limit as the length goes to 0 is taken of the net force acting on the string. But how do we end up with the second derivative (curvature of string) of y/x when we do this? What is the logic behind it?


Thank you guys!





Sorry for any mistakes, I don't have my book handy.
 
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Joza said:
don't understand where the left side comes from.
Consider two adjacent segments of string, length Δx, tension T. The components normal to the string of the forces this exerts at their junction are Tdy/dx, the slopes being a little different in each and the signs being opposite. The net force is therefore Td2y/dx2Δx.
 

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