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Equation z = ct + d, z is measured in meters and t in seconds; dimensions of D?

  1. Aug 24, 2012 #1
    1. The problem statement, all variables and given/known data
    In the equation z = ct + d, z is measured in meters and t is measured in seconds. What are the dimensions (units) of d?

    answer options are...
    s/m, m/s, m, s, m*s


    2. Relevant equations



    3. The attempt at a solution

    plugged in m for z, s for t, and m/s for c. solved for D and got 0.
     
  2. jcsd
  3. Aug 24, 2012 #2

    rcgldr

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    Assume that z is not equal to ct, then if you solve for d, what do you get?
     
  4. Aug 24, 2012 #3
    ermm...i'm guessing m?
     
  5. Aug 24, 2012 #4
    Would it make sense to add two terms together that had different units? Like adding 5 meters plus 35 Amperes?
     
  6. Aug 24, 2012 #5

    rcgldr

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    Can you solve for d and show the equation?

    d = ???
     
  7. Aug 24, 2012 #6
    All the individual terms in a physical equation have to have the same units.
     
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