Equations of motion for uniform acceleration

[geordieonline]

Homework Statement

Hi All,

The question That I am stuck on is:

A packing crate has a nass 100kg is allowed to slide down on a ramp until it hit the ground. The friction resistance to motion is 240N. The length of the ramp is 10 m and thehieght of the crate from the ground just before it started to slide is 6m. Calculate the speed of the crate just before it hits the ground

To be perfectly honest, I don't know where to start! What would you work out first, don't want the answer just help on how to tackle the question - what needs to be worked out first?

Homework Equations

g= 10N/Kg

I've found these equations while researching (I think they are relevant):

Speed = Distance / Time

Velocity = speed + Direction

Work = Force x Distance

The Attempt at a Solution

Don't know where to start

Any advice would be most welcome

 

[danago]

The first thing i would do with a question like this is draw a diagram and clearly label it, including all of the forces that are present

 

[geordieonline]

Cheers Dango

I Have a diagram, but don't know what or how to tackle the question?

Dont know how gravity / crate weight vs friction is worked out with an incline plane?

Would like some advice, direction as what to calculate first - I aint got a clue, have searched wikipedia etc and still don't understand stand

 

[turdferguson]

A problem like this is probable easier in terms of energy conservation

 

[Mentz114]

Do you know how to resolve a force into its horizontal and vertical parts ?

You also need this formula

acceleration = force/mass

 

[harmeet_angel]

I think it's way easier if you use work formula:
change in energy = force applied in that direction x distance

ignore everything else, and find the net force in the direction that object is moving
and only energy changing i kinetic energy

 

[sidrox]

Work done by Friction + Work done by gravity = Final K.E. - Initial K.E.

<i hope this is right!>
now, u can work out the individual work done and find v.