- #1
miniradman
- 196
- 0
equations of planes and the meaning of the "d" value
Find the equations of the following plane
Through (2, 0, 2), (0, 1, 2) and (2, 1, -1)
standard form of equation of a plane:
[itex]ax + by + cz = d[/itex]
hello
I'm trying to conceptually understand how to derive the value for "d".
I understand to find the a b and c coefficients you find the vectors which make the outside of the plane, take the cross product of the two to find the normal vector and then using that result. However, in my solutions it tells me that
"since (2; 0; 2) is in the plane d = 10"
But I have no idea on how that works. I've searched online and had answers such as "d is the distance from the origin" which makes sense. But the magnitude of those three points or the coefficients of the plane do not equal to zero. I can't figure out the algorithm to find "d", does anyone know?
Thanks
- miniradman
Homework Statement
Find the equations of the following plane
Through (2, 0, 2), (0, 1, 2) and (2, 1, -1)
Homework Equations
standard form of equation of a plane:
[itex]ax + by + cz = d[/itex]
The Attempt at a Solution
hello
I'm trying to conceptually understand how to derive the value for "d".
I understand to find the a b and c coefficients you find the vectors which make the outside of the plane, take the cross product of the two to find the normal vector and then using that result. However, in my solutions it tells me that
"since (2; 0; 2) is in the plane d = 10"
But I have no idea on how that works. I've searched online and had answers such as "d is the distance from the origin" which makes sense. But the magnitude of those three points or the coefficients of the plane do not equal to zero. I can't figure out the algorithm to find "d", does anyone know?
Thanks
- miniradman